A Riddle Laugh Or Two

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Postby Elizabeth Hall » Thu Jun 02, 2005 13:59

Aren't we good!!! :D
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Postby Ian Linden » Thu Jun 02, 2005 16:09

I follow the answer, but fail to comprehend the connection with thirteen (or any other number) of beers, although (sniff) it seems rather excessive consumption :flaming:

Yrs, etc
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Postby Andrew Milne » Thu Jun 02, 2005 16:13

The number of beers clue is just to narrow down the possible numbers the ages could be. Hence the 9, 2 and 2 or 6, 6 and 1 both having the sum of 13. Of course the people having the conversation would know how many beers they had had and therefore would be able to work it out.

Of course the answer could be 6, 6 and 1 as out of the two 6 year olds one had to be born before the other and is therefore older.
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Postby Ian Linden » Thu Jun 02, 2005 16:19

Andrew Milne wrote:... Of course the people having the conversation would know how many beers they had had and therefore would be able to work it out....

They may well, but we did not. Perhaps I should have used Ed's expression for D(t+1), or does it only work for tea :?:
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Postby Ed Swindell » Thu Jun 02, 2005 16:41

my equations only ever work tea, i never work with coffee.
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Postby Elizabeth Hall » Thu Jun 02, 2005 18:45

Andrew Milne wrote:Of course the answer could be 6, 6 and 1 as out of the two 6 year olds one had to be born before the other and is therefore older.


Someone has to be picky! :wink:
Really, the beers aren't a clue at all - the main one is the first part
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Postby Andrew Milne » Thu Jun 02, 2005 18:55

Elizabeth Hall wrote:Someone has to be picky! :wink:


Yep and it is usually me lol
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Postby Elizabeth Hall » Thu Jun 02, 2005 18:58

:D
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Postby Lindsey Gray » Fri Jun 03, 2005 09:23

That's teachers for you!!! :wink:
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Postby Andrew Milne » Fri Jun 03, 2005 09:25

Yep :wink:

So where's the new riddle then?
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Postby Lindsey Gray » Fri Jun 03, 2005 09:26

Not my go....
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Postby Andrew Milne » Fri Jun 03, 2005 09:30

:roll:
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Postby Elizabeth Hall » Fri Jun 03, 2005 10:01

Last vacation, my cousin came over to stay at my home. We made the most of her stay at my place... and I even earned a few chocolates.

Everyday, we would play a game of chess. Whoever lost the game owed a chocolate to the other. After the last game we played (that was the day she was to leave), we counted the number of games each of us had won and lost. Wow! I had won more than her. So, she handed me 18 chocolates... though she herself was the winner in 7 games.

How many days did my cousin spend at my place :?:
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Postby Andrew Milne » Fri Jun 03, 2005 10:06

32
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Postby Elizabeth Hall » Fri Jun 03, 2005 10:15

:cheers: Well done! Easy one I guess!
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Postby Andrew Milne » Fri Jun 03, 2005 10:26

This one's not too taxing.

A man travel by car to a destination 25 miles away. The journey was made between 7 and 9am, so the roads were congested and progress was slow. The journey took 75 minutes, which means that his average speed was 20 miles per hour. He took the same route on the return and travelling in the middle of the day made faster time: his return journey lasted just 25 minutes, meaning that his average speed fro the return journey was 60 miles per hour.

What was his average speed for the two journeys combined?
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Postby Elizabeth Hall » Fri Jun 03, 2005 10:52

I hate maths!!

40 :confused:
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Postby Ed Swindell » Fri Jun 03, 2005 11:44

30 mph
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Postby Andrew Milne » Fri Jun 03, 2005 13:36

Correct Ed. The only way to work it out is to add the two distances together and divide it by the time. So (25+25)/100=0.5 0.5*60=30
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Postby Elizabeth Hall » Fri Jun 03, 2005 13:53

I was close!! :roll:
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